#### ~Midnight.Kitten~

##### Junior Member

- Joined
- Jun 27, 2005

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- 87

examplLe: 4x+3y+6+9x+2y+1=

4x+9x= 13 x

3y+2y=5y

6+1=7

*what would i do with the 13x,5y, and 7, do i combine them to, like 13x+5y+7= 25xy?

- Thread starter ~Midnight.Kitten~
- Start date

- Joined
- Jun 27, 2005

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examplLe: 4x+3y+6+9x+2y+1=

4x+9x= 13 x

3y+2y=5y

6+1=7

*what would i do with the 13x,5y, and 7, do i combine them to, like 13x+5y+7= 25xy?

- Joined
- Jun 27, 2005

- Messages
- 87

or, could I add a 1 in front of every x and y, like 1x + 1y =2xy but just keep the two?

- Joined
- Jun 27, 2005

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okay, add the opposite to the 13x and 5 y, would -13x and -5y and then multiply the exponents so 1/13x + 1/5y would come out to be just 13 and 5. so it would be -25?¿~Midnight.Kitten~ said:or, could I add a 1 in front of every x and y, like 1x + 1y =2xy but just keep the two?

G

Well, see if it works. plug in some numbers for x and y, say x = 2, y = 3. The left side is:what would i do with the 13x,5y, and 7, do i combine them to, like 13x+5y+7= 25xy?

13x + 5y + 7

= 13(2) + 5(3) + 7

= 26 + 15 + 7

= 48

The right side is:

25xy

= 25(2)(3)

= 50(3)

= 150

So 13x + 5y + 7 is not the same as 25xy.

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would you multiply the numbers with the numbers in the parenthese?

25(2)(3)

25(2)(3)

G

25xy means 25 * x * y, and I just replaced x with 2 and y with 3, so I got 25 * 2 * 3, which is 150.

- Joined
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i thought so i just wanted to make sure