complex fractions

dude3833

New member
Joined
Aug 2, 2005
Messages
1
i have no idea how to go about answering

1/p - 1/q
________

1/p-q

please help
 

Gene

Senior Member
Joined
Oct 8, 2003
Messages
1,904
Guessing you mean
Code:
    1/p - 1/q 
    _________ =
     1/(p-q)

     (p-q)    (p-q)
   - _____ *  _____ =
      qp        1

    -(p-q)^2
    _________
        pq
   
`
if that is where you are going.

(BTW we would prefer to write it
(1/p-1/q)/(1/(p-q))
 

Denis

Senior Member
Joined
Feb 17, 2004
Messages
1,445
dude3833 said:
i have no idea how to go about answering
1/p - 1/q
________

1/p-q
please help
Is the denominator 1/p - q or 1/(p - q)?

AND: "answering" what? What's the question?
 

ChaoticLlama

Junior Member
Joined
Dec 11, 2004
Messages
199
1/p - 1/q
________

1/p-q

I am assuming what you wrote is supposed to look like this

Code:
1     1
_  -  _
p     q
______
   1
______
(p - q)
That is the same as writting:

Code:
(1     1)
(_  -  _) * (p - q)
(p     q)
Make a common denominator for the terms within the brackets and evaluate

Code:
(q - p)
(_____) * (p - q)
(  qp )
I would then factor a -1 out of the (p - q) to make -( q - p) like so

Code:
(q - p)
(_____) * -(q - p)
(  qp )
then..

Code:
-(q - p)²
_________
   qp
Edit: wow.. all 3 of us fighting to answer this guys questions.... at 1:45 in the morning.

See what too much math does to people? :shock:
 

Gene

Senior Member
Joined
Oct 8, 2003
Messages
1,904
At least we didn't disagree :twisted:
 
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