# complex fractions

1/p - 1/q
________

1/p-q

#### Gene

##### Senior Member
Guessing you mean
Code:
    1/p - 1/q
_________ =
1/(p-q)

(p-q)    (p-q)
- _____ *  _____ =
qp        1

-(p-q)^2
_________
pq


if that is where you are going.

(BTW we would prefer to write it
(1/p-1/q)/(1/(p-q))

#### Denis

##### Senior Member
dude3833 said:
1/p - 1/q
________

1/p-q
Is the denominator 1/p - q or 1/(p - q)?

AND: "answering" what? What's the question?

#### ChaoticLlama

##### Junior Member
1/p - 1/q
________

1/p-q

I am assuming what you wrote is supposed to look like this

Code:
1     1
_  -  _
p     q
______
1
______
(p - q)
That is the same as writting:

Code:
(1     1)
(_  -  _) * (p - q)
(p     q)
Make a common denominator for the terms within the brackets and evaluate

Code:
(q - p)
(_____) * (p - q)
(  qp )
I would then factor a -1 out of the (p - q) to make -( q - p) like so

Code:
(q - p)
(_____) * -(q - p)
(  qp )
then..

Code:
-(q - p)²
_________
qp`
Edit: wow.. all 3 of us fighting to answer this guys questions.... at 1:45 in the morning.

See what too much math does to people? :shock:

#### Gene

##### Senior Member
At least we didn't disagree :twisted: