- Thread starter danj
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You should use grouping symbols so that the meaning of your expressions are clear. I assume the equation isThe question says the given equation is either linear or equivalent to a linear equation. Solve the equation

sqrt 3x + sqrt 12 = x+5/sqrt of 3

I was thinking of trying to rationalize the denominator? Could you help me out?

\(\displaystyle \sqrt{3}\,\, x\, + \sqrt{12}\, =\, \frac{x\, +\, 5}{\sqrt{3}}\)

or possibly

\(\displaystyle \sqrt{3}\,\, x\, + \sqrt{12}\, =\, x\, +\, \frac{5}{\sqrt{3}}\).

In either case what would happen if you multiplied through by \(\displaystyle \sqrt{3}\)?

I'm having a lot of trouble.You should use grouping symbols so that the meaning of your expressions are clear. I assume the equation is

\(\displaystyle \sqrt{3}\,\, x\, + \sqrt{12}\, =\, \frac{x\, +\, 5}{\sqrt{3}}\)

or possibly

\(\displaystyle \sqrt{3}\,\, x\, + \sqrt{12}\, =\, x\, +\, \frac{5}{\sqrt{3}}\).

In either case what would happen if you multiplied through by \(\displaystyle \sqrt{3}\)?

I got

=3x + 3 + (sq 3 x 2) = sqrt 3 (x+5) / sqrt 3

sorry I am having trouble using grouping symbols

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Please show your steps, so we canI'm having a lot of trouble.

What is on the left-hand side of the "equals" sign?I got

=3x + 3 + (sq 3 x 2) = sqrt 3 (x+5) / sqrt 3

They're just parentheses, brackets, or braces; they're just characters which group things together. And, until we know what the intended grouping is, we cannot be sure what you're saying. Sorry.sorry I am having trouble using grouping symbols

Working on the left-hand side of the equation, do you mean either of the following?The question says the given equation is either linear or equivalent to a linear equation. Solve the equation

sqrt 3x + sqrt 12 = x+5/sqrt of 3

. . . . .\(\displaystyle \mbox{a. }\, \sqrt{\strut 3x\,}\, +\, \sqrt{\strut 12\,}\)

. . . . .\(\displaystyle \mbox{b. }\, \sqrt{\strut 3\,}\, x\, +\, \sqrt{\strut 12\,}\)

Working on the right-hand side of the equation, so you mean either of the following?

. . . . .\(\displaystyle \mbox{c. }\, x\, +\, \dfrac{5}{\sqrt{\strut 3\,}}\)

. . . . .\(\displaystyle \mbox{d. }\, \dfrac{x\, +\, 5}{\sqrt{\strut 3\,}}\)

It was suggested that you try multiplying through by the square root of three. In your reply, the first part of your "equation" (the part that followed the first "equals" sign) seems to have four terms. Since the original equation appeared only to have two terms on the left-hand side, clearly there is some confusion somewhere.

When you reply, please show all of your steps. Thank you!