Cramer's Rule: use to solve 4x - y = 2, 4x + 2y = -3

JMM90

New member
Joined
Sep 28, 2006
Messages
9
I'm having problems with trying to solve using Cramer's Rule. The problem is to solve for x in:

. . .4x -.. .y =..2
. . .4x + 2y = -3

I determined the determinant to be 12. Is that right?

Then I put x equal to:

. . .|..2. .-1 |
. . .| -3. ..2 |
. . .----------
. . . . .12

This led to (4 - 3) / 12. Then I put y equal to:

. . .| 4. ..2 |
. . .| 4. .-3 |
. . .----------
. . . . .12

This led to 20 / 12.

Am I totally on the wrong track?
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Edited by stapel -- Reason for edit: restoring formatting
 

galactus

Super Moderator
Staff member
Joined
Sep 28, 2005
Messages
7,216
You're on the right track.

\(\displaystyle \L\\(\frac{1}{12},\frac{-5}{3})\) is correct.
 
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