The answer is 4.5 hrs. BUT how do you set this problem up to solve?!?!?!

- Thread starter kemccla
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The answer is 4.5 hrs. BUT how do you set this problem up to solve?!?!?!

- Joined
- Feb 20, 2005

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D1=6T

distance second cyclist travels in time [T-3],D2 at 10 mph

D2=[T-3]10

when are the distances the same?

D1=D2

6T=10[T-3]

6T=10T-30

30=4T

T=7.5 hours after first cyclist starts, or he will catch up in 4.5 hours

I suggest you do the problem another way!

the first cyclist is how far ahead at the time the second cyclist starts?

How fast is the second cyclist catching up to the first?

How long does it take to catch up?

Arthur

- Joined
- Feb 20, 2005

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- 854

you are welcome

Arthur

Arthur