# Determine if the following points satisfy the equation

G

#### Guest

##### Guest
Determine which of the following points satisfy the inequality:

2x > 3y –5 ( 1, 7/3) (0, 5/3) (3, 7/3)

2(1)>3(7/3)-5
2>16/3-5
2>5 1/3-5
2>1/3 which is true

2(0)>3(5/3)-5
0>14/3-5
0>4 1/3-5
0>-2/3 which is false

2(3)>3(7/3)-5
6>16/3-5
6>5 1/3-5
6>1/3 which is true

Are any of the above correct?

#### stapel

##### Super Moderator
Staff member
For the first one, how did you get that (3/1)(7/3) equalled 16/3, rather than 7?

For the second one, how did you get that (3/1)(5/3) equalled 14/3, rather than 5? Why do you think that zero is less than a negative number?

For the third one, same question as for the first one.

Eliz.

G

#### Guest

##### Guest
I hate fractions. They confuse me!! :x

2x>3y-5

2(1)>3(7/3)-5
2> 7-5
2>2 Not true

2(0)>3(5/3)-5
0>5-5
0>0 Not true

2(3)>3(7/3)-5
6>7-5
6>2 TRUE! Correct?

#### stapel

##### Super Moderator
Staff member
bethany3168 said:
I hate fractions. They confuse me!!
Then you might want to spend some time working with them, because, as you've seen, they come up a lot. You might also find it helpful to work with the improper fractions, rather than converting back and forth between improper fractions and mixed numbers.

bethany3168 said:
Looks good to me.

Eliz.