Did I solve this problem correctly?

Ladybug

New member
Joined
Jul 11, 2007
Messages
39
The problem goes like this:

A local referendum passed by 137 votes. If 993 votes were cast, how many voters voted against the referendum?

I did this:

(x+137)+x=993
2x+137=993
2x=(993-137)
2x=856
2x/2=856/2 = x=428

428 voters voted against the referendum.

Is that correct? Please? I'm hoping it is...*fingers crossed*

Thanks!
 

jwpaine

Full Member
Joined
Mar 10, 2007
Messages
723
Ladybug said:
The problem goes like this:

A local referendum passed by 137 votes. If 993 votes were cast, how many voters voted against the referendum?

I did this:

(x+137)+x=993
2x+137=993
2x=(993-137)
2x=856
2x/2=856/2 = x=428

428 voters voted against the referendum.

Is that correct? Please? I'm hoping it is...*fingers crossed*

Thanks!
You did it correctly and intuitively constructed the equation.... great job!

let Y = yes, N = no

{N + Y = 993
{Y = N + 137

Solve the system of equations:

N + (N + 137) = 993
N = 428

Good work!
 

Ladybug

New member
Joined
Jul 11, 2007
Messages
39
jwpaine said:
Ladybug said:
The problem goes like this:

A local referendum passed by 137 votes. If 993 votes were cast, how many voters voted against the referendum?

I did this:

(x+137)+x=993
2x+137=993
2x=(993-137)
2x=856
2x/2=856/2 = x=428

428 voters voted against the referendum.

Is that correct? Please? I'm hoping it is...*fingers crossed*

Thanks!
You did it correctly and intuitively constructed the equation.... great job!

let Y = yes, N = no

{N + Y = 993
{Y = N + 137

Solve the system of equations:

N + (N + 137) = 993
N = 428

Good work!

Wow, I did something right for a change! :D Thanks for answering. My math teacher uses alphabet letters for those type of equations too...I've just gotten too used to the x's. Thank you again!
 
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