distance and midpoint for (-1/3, -1/3) and (-1/6, -1/2)

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Given the points (-1/3, -1/3), (-1/6, -1/2),

is the distance just 1/36, and the midpoint (-1/4, -5/12)?
 
How did you get your value for the distance (between the points, I'm assuming)?

Please be specific. Thank you.

Eliz.
 
I have my work for the distance saved as a jpeg document on my computer. Is there a way I can put it in here so you can see it ?
 
Post your image somewhere web-viewable (such as your web page, or at ImageShack, etc), and then provide a link. Or just type out your work here.

Thank you.

Eliz.
 
Okay. this is what I have for the distance:
distancework.jpg




Can I take 1/36 out and would that be the final answer, just 1/36?
 
\(\displaystyle \L \sqrt{\frac{1}{36} + \frac{1}{36}} = \sqrt{\frac{2}{36}} = \frac{\sqrt{2}}{6}\)
 
amandamandy said:
Given the points (-1/3, -1/3), (-1/6, -1/2),
is the distance just 1/36, and the midpoint (-1/4, -5/12)?
Click to expand...
Since formula for distance between 2 points is:
sqrt[(x2 - x1)^2 + (y2 - y1)^2]
does that not make your 1/36 quite "suspicious" :wink:

what is -1/6 - (-1/3) ?

edit: didn't see your last post; good work! simplify sqrt(2/36)
 
amandamandy said:
-3/6 = - 1/2
Is my work for this problem all wrong ?
Click to expand...
Au contraire: ALL CORRECT up to sqrt(1/36 + 1/36) :idea:

Surprised you didn't get -1/6 - (-1/3) correct; should be:
-1/6 + 1/3
= -1/6 + 2/6
= 1/6
 
ooh.. woops, I disregarded the 2nd negative sign.. lol

Thanks.
 
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