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No.mathxyz said:3(x) times 3(x + 1) times 3(2 - x) =

My answer: -27x^3 + 27x^2 + 54

Am I right?

No, but you are close; the correct answer is -27x<sup>3</sup> + 27x<sup>2</sup> + 54x.mathxyz said:3(x) times 3(x + 1) times 3(2 - x) =

My answer: -27x^3 + 27x^2 + 54

Am I right?

Yes Sir; you were most certainly not off by much.mathxyz said:Yes, I forgot to include the variable x with 54. I was not off by much.

Perhaps the Honorable Guido will give you 100%.

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if you were asked to combine them into like terms, would it be possible with the ^3 and ^2Matt said:No, but you are close; the correct answer is -27x<sup>3</sup> + 27x<sup>2</sup> + 54x.mathxyz said:3(x) times 3(x + 1) times 3(2 - x) =

My answer: -27x^3 + 27x^2 + 54

Am I right?

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- Apr 12, 2005

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- 9,790

It must match on all bases and exponents.

x^3 and y^3 No. Same exponent but different bases

x^2 and x^3 No. Same base but different exponents

x*y and x^2 No. Same TOTAL exponent, but not anything else.

x^2*y and x*y^2 No. Same TOTAL exponent, but not anything else.

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or simplify it to :

-3^3 x (x+1) (x-2)

Arthur

-3^3 x (x+1) (x-2)

Arthur