when I divide the first term by the first term y^3/y^2 I get y

then multiple y above by the divisor (y^2-3) I get y^3-3y how can i subtract 11y^2 - 3y they are two different degree

help have I done something wronge in my math

Please help

Thank you

- Thread starter sara
- Start date

when I divide the first term by the first term y^3/y^2 I get y

then multiple y above by the divisor (y^2-3) I get y^3-3y how can i subtract 11y^2 - 3y they are two different degree

help have I done something wronge in my math

Please help

Thank you

- Joined
- Feb 4, 2004

- Messages
- 15,943

I'm not sure I follow...?sara said:(y^3 - 11y^2 + 6) / (y^2 - 3)

when I divide the first term by the first term y^3/y^2 I get y

then multiple y above by the divisor (y^2-3) I get y^3-3y how can i subtract 11y^2 - 3y they are two different degree

You have the following exercise:

Code:

```
---------------------
y^2 - 3 )y^3 - 11y^2 + 0y + 6
```

Code:

```
y
---------------------
y^2 - 3 )y^3 - 11y^2 + 0y + 6
```

Code:

```
y
---------------------
y^2 - 3 )y^3 - 11y^2 + 0y + 6
y^3 - 3y
---------------------
- 11y^2 + 3y + 6
```

Eliz.

- Joined
- Jan 20, 2008

- Messages
- 36

This is a good question. It will most definitely come up on a test (the kind of problem where the powers of the exponents don't go down linearly).

Whenever you are missing a term in your dividend (the part inside the divide symbol), so that the powers of your terms are not consecutive, you should add that term with a zero coefficient (like we did by adding the 0y).

Sometimes it is also helpful to do the same to the divisor (the part on the outside of the divide symbol that you are dividing by). Here I have added a 0y as well.

I also recommend lining up all the like terms in the whole problem in columns.

Code:

```
y - 11 <-- Quotient
______________________
y^2 + 0y -3 ) y^3 - 11y^2 + 0y + 6
_ y^3 + 0y^2 - 3y <-- Subtract (Change signs
________________ of terms this row; add)
- 11y^2 + 3y + 6 <-- Bring down + 6
_ - 11y^2 + 0y + 33 <-- Distribute -11 over y^2-3
_________________
3y - 27 <-- Remainder
```