**I keep getting stuck on this one. I will list include the equation that I wrote on the quiz even though I get the feeling it is far off.**

How many ounces of 50% anti freeze solution should be mixed with 10 ounces of an 80% antifreeze solution to produce a 60% antifreeze solution?

.50x + .8(10) = .60(10+x)

How many ounces of 50% anti freeze solution should be mixed with 10 ounces of an 80% antifreeze solution to produce a 60% antifreeze solution?

.50x + .8(10) = .60(10+x)

Any help would be great. Thank you

Any help would be great. Thank you