would it be 5 < 0 ?Let's begin with the definition:
[MATH]|x|=\begin{cases}-x, & x<0 \\[3pt] x, & 0\le x \\ \end{cases}[/MATH]
You have correctly determined the value of the expression within the absolute value brackets in part a). Using the definition above, can you now state the value of the complete expression (including the absolute value)?
ohh right okay, makes sense now. thank youNo, since -5 < 0 then by the definition I gave:
[MATH]|-5|=-(-5)=5[/MATH]
Before we move on, does that make sense to you?