factoring a quatratic equation

sithdas

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Nov 16, 2010
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10y^2=-5y. Not sure how to do this one. Please help? I know the answers are ,0 and 1/2 but I need to know how to do them.
 

masters

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Mar 30, 2007
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sithdas said:
10y^2=-5y. Not sure how to do this one. Please help? I know the answers are ,0 and 1/2 ?? but I need to know how to do them.
Hi sithdas,

\(\displaystyle 10y^2=-5y\)

First thing, transpose the -5y to the left side setting the equation to zero.

\(\displaystyle 10y^2+5y=0\)

Next, look for common monomial factors. Do you see that 5y is a common factor?

\(\displaystyle 5y(2y+1)=0\)

Now use the zero product property to set each factor to 0 and solve each of them.

You'll discover that one of the solutions is \(\displaystyle -\frac{1}{2}\: \text{not}\: \frac{1}{2}\)
 
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