#### Islandchild

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(3x-4y)(2a+3b)

How can you simplify this equation if there are no common terms?

How would you complete this equation step by step?

- Thread starter Islandchild
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(3x-4y)(2a+3b)

How can you simplify this equation if there are no common terms?

How would you complete this equation step by step?

First of all, some terminology: it is not an equation; there is no equal sign. It is a mathematical expression. You can’t “solve” it, but you can “expand” it: multiply each term in the second part by each term in the first part:(3x-4y)(2a+3b)

How can you simplify this equation if there are no common terms?

How would you complete this equation step by step?

(3x-4y)(2a+3b)

= (3x)(2a) + (3x)(3b) + (-4y)(2a) + (-4y)(3b)

= 6ax + 9bx – 8ay – 12by

Hope that helps.

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Thanks wjm11 for the info! Wierd thing is I actually expanded the expression excactly the same as you did. It just didn't look right so I thought I would double check.

Any chance the expressions below are just as easy to factor?

1) 125x^3 - 8y^3

2) 2(5x-1)^3 - (5x-1)^2

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Islandchild said:Any chance the expressions below are just as easy to factor?

1) 125x^3 - 8y^3

This one is easy, if you recognize that it's a difference of cubes.

(Both 125 and 8 are cubes.)

There are special factoring formulas for both a sum of cubes and a difference of cubes.

2) 2(5x-1)^3 - (5x-1)^2

Hint: Factor out a factor of (5x - 1)^2 from each term, then simplify.

In other words, fill in the blanks below and then simplify what's inside the square brackets.

(5x - 1)^2 * [ ____ - ____ ]

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Hey thanks so much! I feel silly, but when I've been looking at questions for hours on end things start to seem more complicated then they really are

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Do you mean "theRodsh said:Looking for two perfect numbers, the factors of which equals the respective number

CLICK HERE for a Wikipedia page on Perfect Numbers

BTW: You posted your submission at the end of somebody else's discussion. In the future, please use the [NewTopic] button on the board's index page to start your own discussion.