Integral of [2/{(x-2)^(4/3)}] I have used u substitution and have come up with -3/[(x-2)^(1/3)] + C however I have a solver that tells me that the answer is -6/[(x-2)^(1/3)] + C. I can't seem to find any reason for the change in numerator from 3 to 6. Is there anyone who could help me out? Maybe its something obvious but I just can't see it.

Thanks,

Andre