S sandyk109 New member Joined May 7, 2007 Messages 15 Aug 4, 2007 #1 If Gina leaves now and drives at 66 kn/h, she will reach Alton just in time for her appointment. On the other hand, if she has lunch first and leaves in 40 minutes, she will have to drive 90 km/h to make her appointment . How far away is Alton?

If Gina leaves now and drives at 66 kn/h, she will reach Alton just in time for her appointment. On the other hand, if she has lunch first and leaves in 40 minutes, she will have to drive 90 km/h to make her appointment . How far away is Alton?

tkhunny Moderator Staff member Joined Apr 12, 2005 Messages 9,829 Aug 4, 2007 #2 This looks awfully familiar. Please see the response on the other one.

G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,216 Aug 5, 2007 #3 If she leaves 40 minutes later, her time is t-2/3. Because 40 minutes is 2/3 hours. Remember, consistent units. The distance is the same regardless of her speed. Therefore, \(\displaystyle \L\\90(t-\frac{2}{3})=66t\) Solve for t.

If she leaves 40 minutes later, her time is t-2/3. Because 40 minutes is 2/3 hours. Remember, consistent units. The distance is the same regardless of her speed. Therefore, \(\displaystyle \L\\90(t-\frac{2}{3})=66t\) Solve for t.