Geometry: The diagonals of square PQRS intersect at T....

josh90

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Aug 10, 2006
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Hey, I have a geometry question:

The diagonals of square PQRS interesect at T. If PT = 2x + 6 and QS = 6x - 10, find the length of PR.

Would I do "2x + 6+x = 6x - 10"? If anyone can help that would be great. Thx. :D
 
In a square the diagonals bisect each other and are congruent.
Hence, length of QS is twice the length PT.
 
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