HELP IMMEDIATELY!!

JCoupe

New member
Joined
Jun 21, 2005
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13
My final is tomorrow. out of 50 questions i don't get these 4. can somebody help me out and show me how to do it..


What is equivalent to

4+i
------
2-3i


Simplify

(x^5y^3)^3
---------------------
x^3y^-2*x^8y^-6


In 1995, the population of Mexico was approximately 9.37*10^7 and the land area was 7.62*10^5 square miles. Find the average number of people per square mile in Mexico in 1995.


In the solution (x,y) to the system

{-2x+3y=0
{x-3y=-12

what is the value of x + y?
 
JCoupe said:
What is equivalent to

4+i
------
2-3i
Multiply numerator and denominator by the complex conjugate of the denominator, 2+3i in this case. Simplfy and be amazed.

Simplify

(x^5y^3)^3
---------------------
x^3y^-2*x^8y^-6

I'd do the numerator first: x^15*y^9
Then the denominator x^11*y^(-8)

Is it any easier, now?

In 1995, the population of Mexico was approximately 9.37*10^7 and the land area was 7.62*10^5 square miles. Find the average number of people per square mile in Mexico in 1995.
Division? (9.37*10^7) / (7.62*10^5) = 1.23*10^(7-5) = 1.23*10^2

In the solution (x,y) to the system

-2x+3y=0
x-3y=-12

what is the value of x + y?
Add the two equations;

-x = -12
x = 12

Substitute

12-3y = -12
-3y = -24
y = 8

x+y = ???
 
omg, thank you soooo much.. ur a lifesaver.... i went from :( to :D in a matter of seconds..
 
Hello, JCoupe!

What is equivalent to

4+i
------
2-3i
We must "rationalize" the denominator.
Multiply top and bottom by the conjugate of the denominator.

. . . .4 + i . .2 + 3i . . . . 8 + 12i + 2i + 3i<sup>2</sup> . . . . .8 + 14i - 3 . . . .5 + 14i
. . . ------- . -------- . = . ---------------------- . = . -------------- . = . ---------
. . . .2 - 3i . 2 + 3i. . . . . . 4 + 6i - 6i - 9i<sup>2</sup> . . . . . . . 4 + 9 . . . . . . . 13


Simplify

. . .(x<sup>5</sup>y<sup>3</sup>)<sup>3</sup>
-----------------
(x<sup>3</sup>y<sup>-2</sup>)(x<sup>8</sup>y<sup>-6</sup>)
.
. . . . . . . . . .(x<sup>5</sup>)<sup>3</sup>(y<sup>3</sup>)<sup>3</sup> . . . . . x<sup>15</sup>y<sup>9</sup>
We have: . -------------- . = . --------- . = . x<sup>4</sup>y<sup>17</sup>
. . . . . . . . . . . x<sup>11</sup>y<sup>-8</sup> . . . . . . x<sup>11</sup>y<sup>-8</sup>


Edit: Too fast for me (again), TK!
 
Well, 88 is pretty good. What's next? Will you be shooting for 90?
 
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