help!!! ln(t^2)+ln(1/T)=4.39 solve for t

[egotripno1]

This one has me stumped!!!

I need to know if I am heading the right direction.

ln(t^2)+ln(1/T)=4.39 solve for t

start out by simplifying the ln statements right

=> 2ln(t)+[-1ln(t)]=4.39

combine like terms.

=> ln(t)=4.39

then I should be able to antiln both sides.

=> t=80.640

Am I right???

 

[soroban]

Hello, egotripno1!

This one has me stumped!!!

I guess not . . . you got it right!

 

[stapel]

To check the solution to any "solving" problem, plug your answer back into the original problem. In this case, plug "80.640" in for "t", and make sure that the result is "true" (after accounting for round-off error).

Eliz.

 

[egotripno1]

it wasn't for lack of effort, i spent about 2 hrs trying to simplify it using ever "law of exponent" and "law of ln" I could remember.

Thanks for your confirmation.

 

[dagr8est]

Hehe 2 hours? You have infinately more patience than I.

Do you know the log rule that log(x)+log(y)=log(xy)? Similarily, log(x)-log(y)=log(x/y). That could save you a lot of time in the future.