Help please

G

Guest

Guest
Write an equation of the line that passes through the point (3,0) and is parallel to the line 2x+6y=-5

My book says the answer is y=-1/3x + 1

This is what I did:

6y=2x+-5

6y = 2x + -5
___ ___ ____
6 6 6

y=1/3x+-5/6


what am I doing wrong??????? Thanks so much.
 

stapel

Super Moderator
Staff member
Joined
Feb 4, 2004
Messages
15,943
How did you move "2x" to the other side of the equation without changing its sign?

Eliz.
 

Denis

Senior Member
Joined
Feb 17, 2004
Messages
1,465
afreemanny said:
Write an equation of the line that passes through the point (3,0) and is parallel to the line 2x+6y=-5
My book says the answer is y=-1/3x + 1
This is what I did:
6y=2x+-5
6y = 2x + -5
___ ___ ____
6 6 6
y=1/3x+-5/6
what am I doing wrong??????? Thanks so much.
I don't follow what "you did"; we have:
2x + 6y = -5 ; then:
6y = -2x - 5
y = (-2/6)x - 5/6
y = (-1/3)x - 5/6

so slope of new line is -1/3 (since parallel); you ok now?
 

ChaoticLlama

Junior Member
Joined
Dec 11, 2004
Messages
199
Standard equation of a line is

y = mx + b

where m is slope, b is the y intercept, and y and x are coordinates.

Find the slope of this line: 2x+6y=-5 by putting it into the standard form

2x + 6y = - 5

6y = -2x - 5

y = -1/3x - 5/6

so m = -1/3

and it gives a point on the line, (0,3)

So it looks as if you have the slope, and a point, plug those into the standard equation and solve for the y-int
 

Denis

Senior Member
Joined
Feb 17, 2004
Messages
1,465
Gee, manny, you got 3 replies in 3 minutes: 3.35, 3.36 and 3.37 !
...at FreeMath's, we do it all for you...
 
G

Guest

Guest
Thanks

Looks like I was on the right start. I appreciate everybodys help. :D
 
Top