Help solving for X in 2x - x^2 = -x

havenoclu

New member
Man..been a long time since I've looked at a math problem. Can someone please help me solve for x in this equation:

2x - x^2 = -x

I would like to know each step. TIA!

stapel

Super Moderator
Staff member
A good first step might be to add x to either side. Then factor, and solve the linear factors.

Eliz.

havenoclu

New member
oh man! all the way back to beginning algebra eh? haha. thanks for the quick reply.

so...

maybe something like...

2x - x^2 + x = 0 ???

stapel

Super Moderator
Staff member
havenoclu said:
...something like 2x - x^2 + x = 0 ?
Simplify: What is 2x + x?

Then factor.

Then use the "zero factor property" to solve the factors. (Reminder: If you multiply two things and get zero, what must at least one of the things be equal to?)

Eliz.

havenoclu

New member
3x - x^2 = 0

I suppose something must be equal to 0?

havenoclu

New member
stapel said:
Then use the "zero factor property" to solve the factors...
Using the "zero factor property" would make x=0??

3(0) - 0^2 = 0 ??

stapel

Super Moderator
Staff member
Or, one could try following the step-by-step instructions: Factor. Then apply the "zero FACTOR property" (explained previously) to solve the FACTORS.

Eliz.

havenoclu

New member
stapel said:
Or, one could try following the step-by-step instructions: Factor. Then apply the "zero FACTOR property" (explained previously) to solve the FACTORS.

Eliz.
i forgot how to factor...but i suppose x=3...so how would i come to that by factoring?

stapel

Super Moderator
Staff member
havenoclu said:
i forgot how to factor...
This site has a free lesson which should help you study this topic:

. . . . .java-applet algebra lessons

Look in the right-hand column, and click on "Factoring Polynomials" and/or "Factoring Quadratics".

Eliz.