#### Andyisvenom

##### New member

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Currently in class and idk what to do i cant fail this can someone help me out

- Thread starter Andyisvenom
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- Oct 22, 2013

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Currently in class and idk what to do i cant fail this can someone help me out

- Joined
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If, as you appear to be saying, you have no idea at all how to do these problems (I don't know what problems they are as you did not even properly upload them) why

What's

- Joined
- Jun 18, 2007

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http://s7.postimg.org/pl9pjmhtn/image.jpg[\img][/QUOTE]

I do commend you for your honesty (while trying to cheat)!!

You could have pretended to be grandpa trying to help grandson and all that.....

If you were skillful enough to upload your problems - somebody may have taken that hook, line and sinker .............

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Solve the following, using \(\displaystyle a\, =\, 3,\, b\, =\, 4, c\, =\, \frac{1}{3},\, d\, =\, \frac{1}{2},\, m\, =\, 6,\, \) and \(\displaystyle n\, =\, \frac{1}{4}\).

17. \(\displaystyle \displaystyle{\frac{\sqrt{b}\, +\, \sqrt{2d}}{2}\, -\, \frac{\sqrt{3c}\, +\, \sqrt{8d}}{4}}\)

18. \(\displaystyle \displaystyle{\frac{2\sqrt{a^2 b^2}}{3}\, +\, \frac{3\sqrt{2\, +\, d^2}}{4}\, -\, a\sqrt{n}}\)

Solve the following, using \(\displaystyle a\, =\, 2,\, b\, =\, \frac{1}{3}, x\, =\, -2,\, y\, =\, -1,\, m\, =\, 3,\, \) and \(\displaystyle n\, =\, \frac{1}{2}\).

16. \(\displaystyle \displaystyle{\frac{3a}{x}\, +\, \frac{2y}{m}\, +\, \frac{3n}{y}\, -\, \frac{m}{n}\, +\, 2\left(x^3\, -\, y^2\, +\, 4\right)}\)

Solve each system of equation

16. \(\displaystyle \displaystyle{\begin{cases}x\, =\, -\frac{3y\, +\, 3}{4}\\y\, =\, -\frac{1\, +\, 5x}{4}\end{cases}}\)

17. \(\displaystyle \displaystyle{\begin{cases}\frac{x\, +\, y}{6}\, =\, \frac{x\, -\, y}{12}\\\frac{2x}{3}\, =\, y\, +\, 3\end{cases}}\)

18. \(\displaystyle \displaystyle{\begin{cases}3x\, -\, \frac{y\, -\, 3}{5}\, =\, 6\\3y\, -\, \frac{x\, -\, 2}{7}\, =\, 9\end{cases}}\)

Yes, that's the numbering in the image.

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