finding the limit x aproaches 2 from the right [absolute (x-2)]/x-2 , any hints would be awsome :).
W warsatan New member Joined Sep 12, 2005 Messages 36 Sep 19, 2005 #1 finding the limit x aproaches 2 from the right [absolute (x-2)]/x-2 , any hints would be awsome .
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,583 Sep 19, 2005 #2 When x > 2, what is the sign on x - 2? So what is the simplification of |x - 2|? So what is the simplification of |x - 2|/(x - 2)? Eliz.
When x > 2, what is the sign on x - 2? So what is the simplification of |x - 2|? So what is the simplification of |x - 2|/(x - 2)? Eliz.
W warsatan New member Joined Sep 12, 2005 Messages 36 Sep 19, 2005 #3 stapel said: When x > 2, what is the sign on x - 2? So what is the simplification of |x - 2|? So what is the simplification of |x - 2|/(x - 2)? Eliz. Click to expand... how do you simplify that? , when x>2 the sign is positive (+). i'm really stuck here,
stapel said: When x > 2, what is the sign on x - 2? So what is the simplification of |x - 2|? So what is the simplification of |x - 2|/(x - 2)? Eliz. Click to expand... how do you simplify that? , when x>2 the sign is positive (+). i'm really stuck here,
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,583 Sep 19, 2005 #4 So if x - 2 is positive, how do you write "|x - 2|" without the bars? Eliz.
W warsatan New member Joined Sep 12, 2005 Messages 36 Sep 19, 2005 #5 x+2? i'm trying to understand where you're leadding me to, but so far, i'm still lost
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,583 Sep 19, 2005 #6 Why would |x - 2| become "x + 2"? This is valid only if x = 0. Eliz.
pka Elite Member Joined Jan 29, 2005 Messages 11,971 Sep 19, 2005 #7 If x>2 then |x−2|/(x−2) = (x−2)/(x−2). If x<2 then |x−2|/(x−2) = −(x−2)/(x−2). BTW: to type | go to the “ \” key. Ten used the shift key.
If x>2 then |x−2|/(x−2) = (x−2)/(x−2). If x<2 then |x−2|/(x−2) = −(x−2)/(x−2). BTW: to type | go to the “ \” key. Ten used the shift key.
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