J josh123 Junior Member Joined Oct 5, 2005 Messages 52 Oct 5, 2005 #1 Can someone show me how to do this and find the answer? Find the center and radius of the circle given by (x - 2)2 + (y + 3)2 = 0.25

Can someone show me how to do this and find the answer? Find the center and radius of the circle given by (x - 2)2 + (y + 3)2 = 0.25

stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 15,943 Oct 5, 2005 #2 When a circle equation is in the form: . . . . .(x - h)<sup>2</sup> + (y - k)<sup>2</sup> = r<sup>2</sup> ...as yours is, just read off the center (h, k) and radius r directly from the equation. Eliz.

When a circle equation is in the form: . . . . .(x - h)<sup>2</sup> + (y - k)<sup>2</sup> = r<sup>2</sup> ...as yours is, just read off the center (h, k) and radius r directly from the equation. Eliz.

J josh123 Junior Member Joined Oct 5, 2005 Messages 52 Oct 5, 2005 #3 so would this be the answer? Center at (-2, 3) and radius equal to 0.5

stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 15,943 Oct 5, 2005 #4 The radius is correct, but check your signs on h and k. For instance, if h = -2, then x - h = x - (-2) = x + 2, but "x + 2" isn't what is in your equation. Eliz.

The radius is correct, but check your signs on h and k. For instance, if h = -2, then x - h = x - (-2) = x + 2, but "x + 2" isn't what is in your equation. Eliz.

J josh123 Junior Member Joined Oct 5, 2005 Messages 52 Oct 5, 2005 #5 is this right? Center at (2, -3) and radius equal to 0.5