nae said:

The above appears to mean the following:

. . . . .\(\displaystyle \L \frac{4}{c}\,=\,4c\,+\,\frac{4}{c(c\,+\,1)}\)

Is this what you meant? Please confirm or correct. Thank you.

nae said:

Could anyone tell me if this is right?

I would assume that you copied the equation correctly from the book. Are the instructions to "solve for the value of the variable c"? Or something else? What were your steps? What was your answer?

Please be specific. Thank you.

Eliz.