I was just practising old questions of my exam and I found this one . Thought it would be easy but I just do not get the right answer which is 7 cocktails. Thanks in advance .

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- Thread starter Mark222
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I was just practising old questions of my exam and I found this one . Thought it would be easy but I just do not get the right answer which is 7 cocktails. Thanks in advance .

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[imath]\;[/imath]

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Are you sure that line is correct?Sasha drank twice as much beer as Max, butshedrank three times as much juice than Sasha.

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Maxine?Are you sure that line is correct?

yes Maxine drank three times as much juice as sashaAre you sure that line is correct?

I tried to do with two equations

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B for beer , J for juice , C for cocktails.

For sasha ,x1 B+ x2J + x3 C= 10 x 500

For maxine ,y1B + y2 J + y3 C= 10 x 625

Then ,

Sasha drank twice beer as maxine

2y1B + x2 J + x3 S = 5000

for max three time as much as juice as sasha

y1B + 3x2 J + y3 S = 6250

then I am stuck. Thanks for your replies

yesMaxine?

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Can you please define allI tried to do with two equations

B for beer , J for juice , C for cocktails.

For sasha ,x1 B+ x2J + x3 C= 10 x 500

For maxine ,y1B + y2 J + y3 C= 10 x 625

Then ,

Sasha drank twice beer as maxine

2y1B + x2 J + x3 S = 5000

for max three time as much as juice as sasha

y1B + 3x2 J + y3 S = 6250

then I am stuck. Thanks for your replies

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SB = number of beer Sasha drank

SJ = number of juice Sasha drank.

SC = number of cocktails Sasha drank.

MB = number of beer Max drank

MJ = number of juice Max drank.

MC = number of cocktails Max drank.

They each drank 10 drinks during the evening:

1)SB + SJ + SC = 10

2)MB + MJ + MC =10

Sasha drank twice as much beer as Max:

3)SB = 2MB

Max drank three times as much juice than Sasha:

4)MJ = 3SJ

Sasha spent CZK 500:

5)25SB + 50SJ + 100SC = 500

Max spent CZK 625:

6)25MB + 50MJ + 100MC = 625

6 equation with 6 unknowns might be solvable

Find SC + MC