i completely forgot how to do this

madelynnnnnn

New member
Joined
Apr 6, 2006
Messages
12
ive completely forgot how to do my hw since friday...

Simplify the expression.

sqrt(5/12)
then i think you go...
sqrt(5) / 2sqrt(3)

and then another one is

sqrt(3/7) and in that one i dont see any perfect squares

and then theres some problem where you have to multiply two squareroots of a fraction such as...

sqrt(10/3) times sqrt(9/5)
 

askmemath

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Joined
Apr 28, 2005
Messages
31
First one --- Correct

2nd One --- Correct

3rd One --- Just multiply the two terms as though there were no Square Roots and then find the Square root

You should therefore get \(\displaystyle sqrt( (10/3)*(9/5))\)

\(\displaystyle sqrt(6)\)
 

soroban

Elite Member
Joined
Jan 28, 2005
Messages
5,588
Hello, madelynnnnnn!

Simplify the expressions.

\(\displaystyle \L 1)\;\sqrt{\frac{5}{12}}\)

then i think you go... \(\displaystyle \L\frac{\sqrt{5}}{2\sqrt{3}}\)
This is correct, but you're probably expected to rationalize the denominator.

\(\displaystyle \L\;\;\frac{5}{2\sqrt{3}}\cdot\frac{\sqrt{3}}{\sqrt{3}}\;=\;\frac{5\sqrt{3}}{6}\)



\(\displaystyle \L2)\; \sqrt{\frac{3}{7}}\;\) and in that one i dont see any perfect squares
No, but we have: .\(\displaystyle \L\,\frac{\sqrt{3}}{\sqrt{7}}\) . . . which we must rationalize.

\(\displaystyle \L\;\;\frac{\sqrt{3}}{\sqrt{7}}\cdot\frac{\sqrt{7}}{\sqrt{7}}\;=\;\frac{\sqrt{21}}{7}\)

\(\displaystyle \L3)\;\sqrt{\frac{10}{3}}\,\cdot\,\sqrt{\frac{9}{5}}\)
These can be combined: \(\displaystyle \L\,\sqrt{\frac{10}{3}\cdot\frac{9}{5}} \;=\;\sqrt{6}\)
 
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