- Thread starter janetfizz
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G

janetfizz said:1/3x < 21 :?

1/3x < 21

Multiply both sides by three to get rid of the fraction.

x < 63.

Sorry, I made a really stupid mistake. I wasn't thinking.

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Depending of which it means:

\(\displaystyle \begin{array}{l}

\frac{1}{{3x}} < 21\quad \Rightarrow \quad \frac{1}{{63}} < x \\

\frac{1}{3}x < 21\quad \Rightarrow \quad x < 63 \\

\end{array}\)

EDIT: Aly, before you answer please be sure you know what you are doing!

G

Well, I don't want to do your homework for you, but the help I can give you is so straightforward that it'll give you the answer. I'll help you with the second one, and then I'll give you a hit about the first one.janetfizz said:thank you very much how do you do 5p-7=18 and y-14.4< 18.39

y-14.4 < 18.39

Add 14.4 to both sides.

y < 22.79

For the first one, try adding the seven. Then finish out the problem. See what you get. Always make sure you have your numbers on one side and your variable on the other when working problems like these out.

G

pka said:

Depending of which it means:

\(\displaystyle \begin{array}{l}

\frac{1}{{3x}} < 21\quad \Rightarrow \quad \frac{1}{{63}} < x \\

\frac{1}{3}x < 21\quad \Rightarrow \quad x < 63 \\

\end{array}\)

Please learn to format the question you mean to ask!

EDIT: Aly, before you answer please be sure you know what you are doing!

Gack, you're right. I meant to ask anyway but I automatically assumed, since it appears to be just a basic inequality. I'll bear that in mind next time. Thanks, pka.