I need some help!

S

skyhier

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Sep 15, 2005
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I haven't even turned these in yet, so if you could help me...

Here's what I have to do...

Find the slope of the line that passes through each pair of points. Then determine whether the line rises to the right, falls to the right, is horizontal or is vertical.

18. (6,1) (8,-4)

20. (-6,-5) (4,1)

22. (2.5,3) (1,-9)

Find the slope of the graph of each equation.

24. x + y= 5

26. 2x - y = 5

28. 3x - 4y= 0

Determine the value of r so a line through the points with the given coordinates has the given slope.

30. (r,2) (4,-6) slope= -8/3

32. (r,6) (8,4) slope=1/2

34. Graph a line through (2,6) that has a slope of 2/3

36. Graph a line through (-4,1) that is perpendicular to a line whose slope is -3/2

38. Graph a line through the orgin that is parallel to the graph of x+y=10

40. One line has a slope of 0 and another has an undefined slope, but they both pass through (-3,-3). Graph the lines.

I am doing evens in the book I have. Like I said, can anyone help, please?
 
“Like I said, can anyone help, please?”
Am I wrong, but don’t you really want someone to do your work for you?
At least you could show what you have tried.
Finding the slope is routine. What do you not understand?
Here is an example: (r,5) & (3,6); slope 2/3 find r. Well (6−5)/(1−r)=2/3, solve for r.
 
to many to even attempt to help with actual details. However if you have a go and show where you are stuck...then help will be coming.
Use this guide

straight line equation is y=mx + b
x and y are the coordinates, m is the slope or gradient, b is the y axis intercept (where x=0)

slope , m = (y2-y1)/ (x2-x1)
where one set of points is (x2,y2) and the other is (x1,y1)--it does not matter what order you use for this.

A postive slope rises to the right, a negative slope falls to the right.

Have a go and I will help
 
Do my work? Let's back up a bit. Sorry about the many questions. Just pick one question from each section and show me how to do it. You don't have to do it for me. Just show me the mechaincs on how it's done. Besides, you're not my (no offense, so don't get mad) my slave.
 
Ok the guide listed works for your #18,20 22

#24 -28
rearrange these in the form y=mx +b

so if you have 3x + y =9
then
y = -3x +9 is the required form

the slope for this is the value in front of the "x" = -3

#32 -33
use m = (y2-y1)/(x2-x1)

this is a start for you to have a go.
 
18. (6,1) (8,-4)

(x1,y1) ===(6,1)
(x2,y2) ===(8,-4)

m= (y2-y1)/(x2-x1)
= (-4 - 1) / ( 8 - 6)

= (-5) / 2

as this is a negative slope it falls to the right.

24. x + y= 5

y= -x + 5
y= (-1)x +5

the slope is -1

30. (r,2) (4,-6) slope= -8/3

m = (y2-y1) / (x2-x1)

(-8/3) = (-6 - 2) / ( 4- r)

(-8/3) = (-8) / (4-r)

(-8/3) (4-r) = -8

4-r = -8 (-3/8)

4-r = 24

4- 24 = r

-20 =r

ok back to you
 
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