please help me do this. Iam really lost and do not know where to even begin
D dumb_kid New member Joined Aug 19, 2021 Messages 1 Aug 19, 2021 #1 please help me do this. Iam really lost and do not know where to even begin
skeeter Elite Member Joined Dec 15, 2005 Messages 3,215 Aug 22, 2021 #2 note [imath]y(0)=1[/imath] [math]\frac{d}{dx} \bigg[y(x) = 1+ \int_0^x 2t[1+y^2(t)] \, dt \bigg][/math] [math]\frac{dy(x)}{dx} = 2x[1+y^2(x)][/math] [math]\frac{dy}{1+y^2} = 2x \, dx[/math] finish it …
note [imath]y(0)=1[/imath] [math]\frac{d}{dx} \bigg[y(x) = 1+ \int_0^x 2t[1+y^2(t)] \, dt \bigg][/math] [math]\frac{dy(x)}{dx} = 2x[1+y^2(x)][/math] [math]\frac{dy}{1+y^2} = 2x \, dx[/math] finish it …
