Inverse Proportion: If 6 workers can perform a job in 12 hours, then...

KWF

Junior Member
Joined
Feb 19, 2010
Messages
193
Have I solved the following correctly?


If 6 workers can perform a job in 12 hours, 3 workers working at the same rate can perform the same work in how many hours?


Solution:

x = k/y

x = 6 workers; k = constant; y = 12 hours


6 workers = k/12 hours

k = 72 worker-hours


a = k/b

a = 3 workers; k = constant from above solution; b = unknown hours


3 workers = 72 worker-hours/b

b * 3 workers = 72 worker-hours

b = 72 worker-hours/3 workers = 24 hours
 

Subhotosh Khan

Super Moderator
Staff member
Joined
Jun 18, 2007
Messages
18,246
Have I solved the following correctly?


If 6 workers can perform a job in 12 hours, 3 workers working at the same rate can perform the same work in how many hours?


Solution:

x = k/y

x = 6 workers; k = constant; y = 12 hours


6 workers = k/12 hours

k = 72 worker-hours


a = k/b

a = 3 workers; k = constant from above solution; b = unknown hours


3 workers = 72 worker-hours/b

b * 3 workers = 72 worker-hours

b = 72 worker-hours/3 workers = 24 hours
CORRECT - however a bit long-winded!
 
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