Is there any way to get 17 as answer to following question!!!?

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harish

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When 242 is divided by a certain divisor*the remainder obtained is 8. When 698 is*divided*by the same*divisor*the remainder obtained is 9. However, when the sum of the two numbers*242*and 698 is*divided*by the*divisor, the remainder obtained is 4.

How to solve this to get answer as 17
 
harish said:
When 242 is divided by a certain divisor*the remainder obtained is 8. When 698 is*divided*by the same*divisor*the remainder obtained is 9. However, when the sum of the two numbers*242*and 698 is*divided*by the*divisor, the remainder obtained is 4.

How to solve this to get answer as 17
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I am getting 13 as answer ?..Not 17

(1) 242 = D*N1 + 8

(2) 698 = D*N2 + 9

(3) 242+698=D*N3 + 4

Add (1) and (2) > 698+242 = D*(N1+N2) + 17

Subtract from (3) > D*(N3-N1-N2) = 13
 
harish said:
When 242 is divided by a certain divisor*the remainder obtained is 8. When 698 is*divided*by the same*divisor*the remainder obtained is 9. However, when the sum of the two numbers*242*and 698 is*divided*by the*divisor, the remainder obtained is 4.

How to solve this to get answer as 17
Click to expand...

I don't see a question here! What are you supposed to be looking for, that 17 is the answer to?

If you want the divisor, it isn't 17. (You can easily check that.) So the way to solve it and get 17 is to make a mistake somewhere!

The number 17 is the sum of the two remainders, and can be used as part of a quick method of solution, but I don't see how it can be considered an "answer".

If you do want to find the divisor, and don't need to find the quickest solution, you might start by thinking about what possibilities the first sentence gives you. (What number must be a multiple of this divisor?) Please show whatever work you can do, or whatever ideas you have about things to try.
 
Question is :-When 242 is divided by a certain divisor the remainder obtained is 8. When 698 is divided by the same divisor the remainder obtained is 9. When the sum of the two numbers 242 and 698 is divided by the divisor, the remainder obtained is 4. What is the value of the divisor?*
A)11. B)17. C)13

Solution steps​:-

(1) 242 = D*N1 + 8*

(2) 698 = D*N2 + 9*

(3) 242+698=D*N3 + 4*

Add (1) and (2) > 698+242 = D*(N1+N2) + 17*

Subtract from (3) > D*(N3-N1-N2) = 13
the divisor is a multiple of 13

The answer given for above question is 17....I doubt the given answer is right.while solving I am getting 13
 
Dr.Peterson said:
I don't see a question here! What are you supposed to be looking for, that 17 is the answer to?

If you want the divisor, it isn't 17. (You can easily check that.) So the way to solve it and get 17 is to make a mistake somewhere!

The number 17 is the sum of the two remainders, and can be used as part of a quick method of solution, but I don't see how it can be considered an "answer".

If you do want to find the divisor, and don't need to find the quickest solution, you might start by thinking about what possibilities the first sentence gives you. (What number must be a multiple of this divisor?) Please show whatever work you can do, or whatever ideas you have about things to try.
Click to expand...
Hi Dr Peterson
It's one of the recent recruitment question. Expert has given wrong answer is 17.. correct answer for this question is 13. Some people's are trying to make the answer is 17.. it's impossible to make it... We don't know where this question has been taken for the examination... Is it previously asked question in any entrance or recruitment examination ? Kindly help me Sir
 
How would I know? I don't have a directory of examination questions. All I can do is search, and find many sites where it has been asked, some giving the correct answer.

Don't trust "experts".
 
Hi,
you are wright the remainder is 4.

If remainder is 8 when that divisor divides 242 then that divisor is a factor (242- 8)=234, prime factors of 234 =2*3*3*13
Similarly if remainder is 9 when 698 is divided by a divisor then the divisor must be a factor of (698-9)=689
Prime factors of 689= 13*53
So the only factor common(other than 1) between 234 and 689 is 13 , so C must be the answer.
Lets check the last point : When the sum of the two numbers 242 and 698 is divided by 13 is the remainder indeed 4 ?
242+698= 940.
940 divided by 13 gives remainder 4.
 
AmeliaR said:
Hi,
you are wright the remainder is 4.

If remainder is 8 when that divisor divides 242 then that divisor is a factor (242- 8)=234, prime factors of 234 =2*3*3*13
Similarly if remainder is 9 when 698 is divided by a divisor then the divisor must be a factor of (698-9)=689
Prime factors of 689= 13*53
So the only factor common(other than 1) between 234 and 689 is 13 , so C must be the answer.
Lets check the last point : When the sum of the two numbers 242 and 698 is divided by 13 is the remainder indeed 4 ?
242+698= 940.
940 divided by 13 gives remainder 4.
Click to expand...

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