# keep getting wrong answer

#### wrifalon

##### New member
2x+(6-x)/3=-3 The (6-x)/3 is a fraction (6-x) in the numerator and the 3 is on the bottom.
i get this
2x+(6/3-1/3x=-3
5/3x+6/3=-3
5/3x=-5
x=5
but that not right
what im a doing wrong

#### Denis

##### Senior Member
wrifalon said:
2x+(6-x)/3=-3
i get this
2x+(6/3-1/3x=-3 : NO! Multiply by 3 to get 6x + 6 - x = -9 (if you don't follow that, see your teacher!)

#### wrifalon

##### New member
the (6-x)/3 is a fraction?

the final answer is suppose tobe x=12

#### masters

##### Full Member
Don't think so, unless you miscopied the equation.

Start from where Denis corrected your calculations: After multiplying each term by 3, you get

6x + 6 - x = -9
Combining like terms on the left: 5x + 6 = -9
Subtracting 6 from both sides: 5x = -15
Dividing by 5: x = -3

Check:
2(-3) + (6-[sup:sv19tttr]-[/sup:sv19tttr]3)/3 = -3
-6 + 9/3 = -3
-6 + 3 = -3
-3 = -3

#### wrifalon

##### New member
Thanks, I understand the way you did it, the book answer must be wrong, its happen before, I dont know why they are teaching us to multiply the fraction by the reciprocal, them distribute it then do the undoing to get the answer about 20 steps when the way you did makes more sense and less steps. Thanks again

#### Subhotosh Khan

##### Super Moderator
Staff member
wrifalon said:
2x+(6-x)/3=-3 The (6-x)/3 is a fraction (6-x) in the numerator and the 3 is on the bottom.
i get this
2x+(6/3-1/3x=-3
5/3x+6/3=-3
5/3x=-5<<<<< Right after this - you went wrong

(5/3)* x * (3/5) = -5 * (3/5) <<<<< multiply by 3/5 both sides - to isolate 'x'

x = - 3

You check your answer - by putting it into the original equation:

2x + (6 - x)/3 = 2*(-3) + [6 -(-3)]/3 = -6 + 9/3 = - 6 + 3 = -3 <<<< checks