The edited description helps. You could have typed it as

[2 + 3/(x + 1)]/[1/x + 1]

or hit the C(ode) button twice and typed between the boxes as

Code:

```
2 + 3/(x + 1)
--------------
1/x + 1
```

anyhow start with

2+3/(x+1) = (2(x+1)+3)/(x+1) and

1/x+1 = (x+1)/x

The (x+1)/x inverts to the numerator as a multiplier to get

x(2x+2+3)/(x+1)^2 =

(2x^2+5x)/(x+1)^2

I don't see any more to do with it and I don't agree with the books answer. Something is wrong. If you try x=2 the original gives 2 but the book answer gives 1.2 but whatever you plug in for x you should get the same thing. That's a way of checking the validity of your answers. Try a few different numbers though. The book agrees if x=1.

BTW if you look under

math lessons

at Order of Operations

you will see why your going astray in youe typing.

PS. I had this typed before I saw Denis' post.