- Thread starter newuser
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Suppose you letsolve for x:

log_{5}(x)+(log_{5}(125)/log_{5}(x))=7/2

y=log

and 'simplified' the equation to

y

Solving for y gives me 9/4 and 5/4Suppose you let

y=log_{5}(x)

and 'simplified' the equation to

y^{2}- (7/2) y + log_{5}(125) = 0

and then for x gives me 25(5)

Pls tell me if I'm correct?

The answer in the book is 5 and 5(25)

Thanks for your help

sorry I got y=2 and 3/2Solving for y gives me 9/4 and 5/4

and then for x gives me 25(5)^{1/2 }and 25 resp.

Pls tell me if I'm correct?

The answer in the book is 5 and 5(25)^{1/2}(=25 I calculated,not mentioned in book)

Thanks for your help

x=25 and 5(5)

Which is what I got. If you put those values back in the original equation, i.e. check the answer, I find those are the proper solution.sorry I got y=2 and 3/2

x=25 and 5(5)^{1/2} resp.