mathstresser
Junior Member
- Joined
- Jan 28, 2006
- Messages
- 134
A tank initially conatins 100 gal of a salt-water solution containing .05 lb of salt for each gallon of water. At time zero, pure water is poured into the tank at a rate of 3 gal per minute. Simultaneously, a drain is opened at the bottom of the tank that allows the salt-water solution to leave the tank at a rate of 2 gal per minute. What will be the salt content in the tank when precisely 50 gal of salt solution remain?
v(0)= 100 gallons
The salt content to begin with is .05 lb/gal
The water that pours into the tank is:
3 gal/min
0 lb/gal
The water that drains out is:
2 gal/min
? lb/gal
First of all, how when does only 50 gal of salt solution remain? It starts off with 100 gallons and fills faster than it drains. Secondly, if this problem did make sense, how do we find the formula for the salt content that is draining?
rate in- rate out
rate in= 0
rate out= ?
v(0)= 100 gallons
The salt content to begin with is .05 lb/gal
The water that pours into the tank is:
3 gal/min
0 lb/gal
The water that drains out is:
2 gal/min
? lb/gal
First of all, how when does only 50 gal of salt solution remain? It starts off with 100 gallons and fills faster than it drains. Secondly, if this problem did make sense, how do we find the formula for the salt content that is draining?
rate in- rate out
rate in= 0
rate out= ?