[MOVED] 52 dogs and cats; three times the number of dogs exc

humakhan

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May 19, 2005
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182
A total of 52 dogs and cats were on the ranch. if three times the number of dogs exceeded the number of cats by four , how many of each were on the ranch?

3D + 4C = 52
subtract 4C from both sides
3D = 48
48/3
D=16

3(16) + 4C = 52
48 + 4C = 52
sybtract 48 from both sides
4C = 4
4/4
C = 1

check

3(16dogs) + 4(1cat) = 52 on the ranch
48dogs + 4cats = 52
52dogs&cats= 52 on the ranch

wrong
 

stapel

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Re: [MOVED] 52 dogs and cats; three times the number of dogs

humakhan said:
A total of 52 dogs and cats were on the ranch. if three times the number of dogs exceeded the number of cats by four, how many of each were on the ranch?

3D + 4C = 52
Hint: Look up the word "exceeded". Once you know what it means, you'll know what operation to use.

humakhan said:
cats = 1
dogs = 16
Since 1 + 16 does not equal 52, the above cannot be the correct solution.

Eliz.
 

humakhan

Junior Member
Joined
May 19, 2005
Messages
182
exceeded means :To be greater than

so here is how you write the problem out
3D > 4C = 52
 

Denis

Senior Member
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Feb 17, 2004
Messages
1,467
"exceeds by 4" simply means "4 more"; like 10 is 4 more than 6 :idea:
 
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