L linfinity27 New member Joined Sep 4, 2006 Messages 3 Sep 4, 2006 #1 f(x) = (x + 10)/(x^2 - 289) I need to figure out the domain, and I'm stuck! Thanks in advance for the help!

f(x) = (x + 10)/(x^2 - 289) I need to figure out the domain, and I'm stuck! Thanks in advance for the help!

S soroban Elite Member Joined Jan 28, 2005 Messages 5,588 Sep 4, 2006 #2 Re: domain of a function Hello, linfinity27! Find the domain of: \(\displaystyle \,f(x)\:=\:\frac{x\,+\,10}{x^2\,-\,289}\) Click to expand... Recall that the domain cannot include values which make the denominator equal to zero. This denominator is zero when: \(\displaystyle x^2\,-\,289\:=\:0\;\;\Rightarrow\;\;x^2\:=\:289\;\;\Rightarrow\;\;x\:=\:\pm17\) Therefore, the domain is: all real numbers except 17 and -17.

Re: domain of a function Hello, linfinity27! Find the domain of: \(\displaystyle \,f(x)\:=\:\frac{x\,+\,10}{x^2\,-\,289}\) Click to expand... Recall that the domain cannot include values which make the denominator equal to zero. This denominator is zero when: \(\displaystyle x^2\,-\,289\:=\:0\;\;\Rightarrow\;\;x^2\:=\:289\;\;\Rightarrow\;\;x\:=\:\pm17\) Therefore, the domain is: all real numbers except 17 and -17.