#### crappiefisher26

##### New member

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. . .(2x^3 / 5y^2) * (10y / 3x^2)

. . .= (2x^3 * 10y) / (5y^2 * 3x^2)

. . .= 4x / 3y

- Thread starter crappiefisher26
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- Jul 23, 2006

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. . .(2x^3 / 5y^2) * (10y / 3x^2)

. . .= (2x^3 * 10y) / (5y^2 * 3x^2)

. . .= 4x / 3y

"they got this" by simple multiplication, then simplification :!:crappiefisher26 said:how did they get this.

(2x^3/5y^2)*(10y/3x^2)=(2x^3*10y)/5y^2*3x^2)=4x/3y

EXAMPLE of simplification: x^5 / x^3 = x^(5-3) = x^2

- Joined
- Jul 23, 2006

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Thanks Dennis. Heres the questions im stuck on

3a/2*4/a^2

how did they get 4x/3y from (2x^3*10y)/(5y^2*3x^2)

im not quite sure i understand that yet.

- Joined
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"They" did just what the tutor said: They multiplied the fractions and then simplified.crappiefisher26 said:how did they get 4x/3y from (2x^3*10y)/(5y^2*3x^2)

Are you not familiar with multiplying fractions? Because you can't very well work with rational expressions unless you're very solid on regular (numerical) fractions. If you don't understand how "they" go from, say, (3/5)(20/21) to (1/1)(4/7) = 4/7, then you need to back up a bit before trying to work with rational expressions.

Eliz.