Natural length of a spring

dez88

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Jun 9, 2014
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If 27 J of work are needed to stretch a spring from 17 cm to 23 cm and 45 J are needed to stretch it from 23 cm to 29 cm, what is the natural length of the spring? ................ I need this desperately. I don't even know where to start. We've BRIEFLY solved for K with a known X in our calculus class. I haven't taken physics so this is all new to me. can someone save me? :(
 
If 27 J of work are needed to stretch a spring from 17 cm to 23 cm and 45 J are needed to stretch it from 23 cm to 29 cm, what is the natural length of the spring? ................ I need this desperately. I don't even know where to start. We've BRIEFLY solved for K with a known X in our calculus class. I haven't taken physics so this is all new to me. can someone save me? :(
With spring constant K and calling the natural length L, so that F= K(x- L), the work necessary to stretch the spring from length x1\displaystyle x_1 to x2\displaystyle x_2 is Kx1x2(xL)dx\displaystyle K\int_{x_1}^{x_2}(x- L)dx. Since this is a Calculus class I presume you know that.

The information you are given says that K1723(xL)dx=27\displaystyle K\int_{17}^{23} (x- L)dx= 27 and K2329(xL)dx=45\displaystyle K\int_{23}^{29} (x- L)dx= 45.

Do the integration and you will have two equations to solve for K and L.
 
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