y = (3x+2)/(2x-5) I switched the variables and tried to solve for y, however, the fraction part keeps stumping me. What I've done so far: x=(3y+2)/(2y-5) x(2y-5)=3y+2 x(2y-5)-2=3y [x(2y-5)-2]/3=y Is this correct so far, and how do I proceed?