FrustratedMathMan
New member
- Joined
- Sep 15, 2005
- Messages
- 8
Divive x^3 +27 by x+3
stapel said:Either factor the sum of cubes, using the sum-of-cubes formula, and then cancel. Or else do the long division of x<sup>3</sup> + 0x<sup>2</sup> + 0x + 27 by x + 3.
Which method are you using, and how far have you gotten?
Thank you.
Eliz.
FrustratedMathMan said:stapel said:Either factor the sum of cubes, using the sum-of-cubes formula, and then cancel. Or else do the long division of x<sup>3</sup> + 0x<sup>2</sup> + 0x + 27 by x + 3.
Which method are you using, and how far have you gotten?
Thank you.
Eliz.
I am using long division.
Denis said:Why are you asking that?
The division is by x + 3.
You better go here (can't teach here):
http://www.wtamu.edu/academic/anns/mps/ ... 35_div.htm