numeral system

S

suki7

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Dec 17, 2013
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I realy need help.

131*14=2014
i must know in which number system is this.
i tried with (x^2+3x+1)(x+4)=2x^3+x+4 but the only real solution is 0.
 
suki7 said:
131*14=2014
i must know in which number system is this.
i tried with (x^2+3x+1)(x+4)=2x^3+x+4 but the only real solution is 0.
Click to expand...
By "number system", do you perhaps mean "number base"? What is it that you're "trying"? An algorithm of some sort? What were the instructions for this exercise?

Please be complete. Thank you! ;)
 
Yes i mean base. i just must find number base that 131*14=2014
Q: Alien Math teacher is writing 131*14=2014. how many fingers alien have?
with fingers it is mean humans have 10 fingers - decimal system. aliens have x fingers so i have to find right base
 
Last edited:
suki7 said:
I realy need help.

131*14=2014
i must know in which number system is this.
i tried with (x^2+3x+1)(x+4)=2x^3+x+4 but the only real solution is 0.
Click to expand...
Since the numeral "4" appears in the problem, the base must be 5 or greater.

Carrying out the multiplication on the left side,
\(\displaystyle x^3 + 7x^2 + 13x + 4 = 2x^3 + x + 4\)
and combining like terms
\(\displaystyle x^3 - 7x^2 - 12x = 0\)
Eliminating (by dividing out) the trivial root x=0,
\(\displaystyle x^2 - 7x - 12 = 0\)

That is NOT NICE. Please check that you have the problem copied correctly.
 
Actually - I have been thinking (dangerous) for a while...

How would a "irrational" based number system behave?

Would the number of rational number out-number the "irrationals" in that system?

Would numbers based on π behave differently from numbers based on √2?
 
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