operations question

[skyemonae2]

I need all possible operations: addition, subtraction, multiplication, division, ^, exp, log, etc.. to make the end result 24.


the numbers are 12, 5, 6 & 4


Thanks

 

[jwpaine]

Work it out, trying different things, until you get it...like anyone else would have to.

John.

 

[Denis]

12 / 5 * (6 + 4) = 24

12^(-5+6) * sqrt(4) = 24

12 * 5 - 6^sqrt(4) = 24

Loads more if you don't have to keep 'em in 12-5-6-4 order.

 

[morson]

\(\displaystyle \L\ \frac{0 + (b - b)x^{\theta} + i^2 + 1 + log_e (e^{20 + 4\int_0^1\1dm})}{\frac{6}{\pi\^2}\(Pr(A) + Pr(A^'))\sum_{n=1}^{\infty}\ n^{-2}}\\)

also..

24 + 0

24 - 1 + 1

24e/e

24(idhihdihd)^0, where i, d, h are all nonzero

 

[Denis]

Are you ok, morson? :wink:

 

[morson]

Are you ok, morson? :wink:

bored + wintry day + a lot of free time = strange behaviour in the form of a post :wink:

 

[bebe123abc]

6+4*12/5=24

 

[Denis]

6+4*12/5=24

bebe, that means 4 + 48/5 = 13.6;
brackets required: (6+4) * 12/5 ; same as 12/5 * (6+4)

 

[tkhunny]

Basic 4 operations, as always:

A = 4, B = 5, C = 6, D = 12

 (D/B)x(C+A)      Dx((C+A)/B)      ((C+A)xD)/B      D/(B/(C+A))                  
 (C+A)x(D/B)      Dx((A+C)/B)      ((A+C)xD)/B      D/(B/(A+C))                  
 (A+C)x(D/B)      (Dx(C+A))/B      ((C+A)/B)xD      (C+A)/(B/D)                  
 (D/B)x(A+C)      (Dx(A+C))/B      ((A+C)/B)xD      (A+C)/(B/D)

 

[bebe123abc]

6+4*12/5=24

bebe, that means 4 + 48/5 = 13.6;
brackets required: (6+4) * 12/5 ; same as 12/5 * (6+4)

Thanks for the tip Denis.