ordered oairs that are solutions to y=(2/3)x-1

Sambo

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Aug 19, 2007
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Can someone give me three ordered pairs that are solutions to the equation y=(2/3)x-1? And explain how you got the answers
 

royhaas

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Dec 14, 2005
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Just pick three distinct values of x and calculate y.
 

Sambo

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Aug 19, 2007
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still dont understand. can anybody else help or show me how to do this?
 

Mrspi

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Dec 17, 2005
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Sambo said:
Can someone give me three ordered pairs that are solutions to the equation y=(2/3)x-1? And explain how you got the answers
royhaas told you what to do....pick three different values for x, substitute them (one at a time) into your equation, and find the value of y which corresponds to each value of x.

I'll "walk you through" finding one ordered pair. I will pick 9 as a value for x. I'll substitute 9 for x in the equation:

y = (2/3)x - 1
y = (2/3)*9 - 1
y = 6 - 1
y = 5

So, when x = 9, y = 5 and the ordered pair (9, 5) is a solution to the equation.

Ok...you pick two more values for x and do the same thing. You might note that since you will be multiplying x by 2/3, it may simplify matters if you choose a multiple of 3 for x.
 

Sambo

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Aug 19, 2007
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thanks i see now
 
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