P(a∩b): Given P (A) ≥ 0.99 and P (B) ≥ 0.97, show that P (A∩B) ≥ 0.96
hi guys, i'm brand new to these probability themes and so confused about many of it's problems. So i have a question and hope you guys could help.
In a finite probability space (Ω, P) let A and B be events with P (A) ≥ 0.99 and P (B) ≥ 0.97. Show that P (A∩B) ≥ 0.96.
as i know when A and B independent are, P (A∩B) would = P (A) * P (B) and that would be easy to show. But since the task doesn't mention anything about it, how could i know if A and B independent or not or which way should i use to calculate P (A∩B) ? Thank you!
hi guys, i'm brand new to these probability themes and so confused about many of it's problems. So i have a question and hope you guys could help.
In a finite probability space (Ω, P) let A and B be events with P (A) ≥ 0.99 and P (B) ≥ 0.97. Show that P (A∩B) ≥ 0.96.
as i know when A and B independent are, P (A∩B) would = P (A) * P (B) and that would be easy to show. But since the task doesn't mention anything about it, how could i know if A and B independent or not or which way should i use to calculate P (A∩B) ? Thank you!