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perfect squares and factoring

Kelsey Lunde

New member
Joined
Dec 7, 2009
Messages
1
My problem is
p^2-6/5p+9/25=0

I am really having trouble with this and have no clue where to start.
 

chrisr

Full Member
Joined
Nov 29, 2009
Messages
355
9/25 is 3/5 multiplied by 3/5
It is also -(3/5) multiplied by -(3/5).

Since (a-b)(a-b) is a[sup:1jzvf0n7]2[/sup:1jzvf0n7]-ab-ab+b[sup:1jzvf0n7]2[/sup:1jzvf0n7]

Also, two values multiply to give zero, what can those values be?
This is the reason for writing factors.

can you try it now?
 

Subhotosh Khan

Super Moderator
Staff member
Joined
Jun 18, 2007
Messages
18,091
Kelsey Lunde said:
My problem is
p^2-6/5p+9/25=0

I am really having trouble with this and have no clue where to start.
You do not say - what do you need to do?
 
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