#### vermonstervt

##### New member

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- Jul 24, 2005

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simplify adding like terms

xym-3ymx+4xmy-3my+2ym Please explain step by step thanks

xym-3ymx+4xmy-3my+2ym Please explain step by step thanks

- Thread starter vermonstervt
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- Joined
- Jul 24, 2005

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simplify adding like terms

xym-3ymx+4xmy-3my+2ym Please explain step by step thanks

xym-3ymx+4xmy-3my+2ym Please explain step by step thanks

G

Notice there are like terms in this equation. So combine it.xym-3ymx+4xmy-3my+2ym

xym-3ymx+4xmy-3my+2ym

3my and 2ym are the same. Just to let you know. So just combine like-terms and there you go. Also notice the variables xym, ymx, and xmy are the same. They're just rewritten in different order.

- Joined
- Jul 24, 2005

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-a(b-a) if a=-4 b=-3

-4(1)=-4

If not correct please explain step by step thanks

- Joined
- Jul 24, 2005

- Messages
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a^2-b^2a if a=-2 b=3

-2^2-3^2-2

-4-4-2=-13-2=-15

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-x^2-y^3 if x=-3 y=-2

-3^2-2^3

-9-8=-17

You have the right idea but are careless with your signs. -a(b-a) if a=-4 b=-3

-(-4)((-3)-(-4)) =

(4)(1) = 4

Study this one then try the next one again keeping the variables in ()s whenyou substitue.

G

say that x=5,

y=3

& m= 2.

the order in which the 3 numbers would be multiplyed wouldn't affect the result.

5 times 3 times 2 will equal 30

and so will

3 times 2 times 5.

Now,

knowing that,

xym is the same thign as ymx and the same thing as xmy,

if xym=ymx

then xym(also ymx) + 3ymx would = 4 ymx. Right? follow with me here.

Then, concluding everything else i explained, then 4 ymx would be the same thing as 4xmy.

so,

4ymx(also 4xmy) + 4xmy= 8 xmy.

_____________________________________________

Part 2.

now the other part of the equation left would be 3my+2ym.

Since that whole part is SUBTRACTED from the other half,

you need to simplify that part seperately from the other part.

as i said, before, 3my could be the same thing as 3ym, so

3my(also 3ym) + 2ym= 5ym.

:?: :idea: :!: THE ANSWER IS::: 8xmy-5ym

G

NOW EVERYONE!!!

stop messing with the problem ANYMORE> thankyou.

stop messing with the problem ANYMORE> thankyou.

- Joined
- Feb 4, 2004

- Messages
- 15,943

Um... you're the only one "messing" with threads. Kindly start helping people, or else please take your chat-room behavior elsewhere. Thank you.beautifull_love101 said:NOW EVERYONE!!!

stop messing with the problem ANYMORE> thankyou.

Eliz.