- Thread starter adevine
- Start date

I'm not sure where you got your "934" in your equation.

The area of the pool with the sidewalk is (2x + 50)(2x + 25), which is 4x[sup:3obn90da]2[/sup:3obn90da] + 150x + 1250

Now, if you subract the area of the pool (25)(50) = 1250, you will have the area of the sidewalk which is 316 m[sup:3obn90da]2[/sup:3obn90da].

(4x[sup:3obn90da]2[/sup:3obn90da] + 150x + 1250) - 1250 = 316

Simplifying, 2x[sup:3obn90da]2[/sup:3obn90da] + 75x -158 = 0

This factors into (x - 2)(2x +79) = 0

x = 2 or x = -79/2

Since x cannot be negative (it's a length), then the sidewalk is 2 meters wide.

adevine said:

Hi folks,

I am having some trouble with this seemingly simple problem. I keep getting to:

4x^2+150x+934=0

But I can't find a way to factor that equation like I am used to doing. Any help would be appreciated. Thanks!

Alternatively:

2(50 + 2x) + 2(25)x = 316 or 2x^2 + 75x - 158 = 0 leading to the same answer as adevine came up with.