- Thread starter krisolaw
- Start date

Well, since you were considerate enough to tell us that these are 2 points, and a slope, then:krisolaw said:This is the problem I have, but I am not sure how to go about it. Could someone please help or explain? Thanks in advance.

Solve for b: (5,b^2), (2,4b), m=-1

(b^2 - 4b) / (5 - 2) = -1

b^2 - 4b = -3

b^2 - 4b + 3 = 0

(b - 3)(b - 1) = 0

b = 3 or b = 1

If that don't ring your chimes, look up "slope"...if you're not too tired...